16x^2-10x+8x-5=0

Solution for 16x^2-10x+8x-5=0 equation:

16x^2-10x+8x-5=0

We add all the numbers together, and all the variables

16x^2-2x-5=0

a = 16; b = -2; c = -5;
Δ = b2-4ac
Δ = -22-4·16·(-5)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-18}{2*16}=\frac{-16}{32}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+18}{2*16}=\frac{20}{32}
=5/8
$